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house-robber
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house-robber/changhyumm.py

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class Solution:
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def rob(self, nums: List[int]) -> int:
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n = len(nums)
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# 집이 하나면 최대 profit은 그 자체
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if n == 1:
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return nums[0]
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# dp[i]를 i+1 집까지 털었을때의 max라고 정의
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# dp[i] = max(dp[i-1], nums[i] + dp[i-2])
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dp = [0] * n
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dp[0] = nums[0]
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dp[1] = max(nums[0], nums[1])
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# dp를 누적
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for i in range(2, n):
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dp[i] = max(dp[i-1], nums[i] + dp[i-2])
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# time O(n) - loop 1번
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# space O(n) - dp 배열
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return dp[-1]

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